Russian Roulette probability question

Question

You are playing a game of Russian Roulette. If instead of one bullet, two bullets are randomly put in the chamber. Your opponent played the first and he was alive after the first trigger pull. You then spin the barrel. What is the probability that you loose in this round?

Answer 1

You have 6 slots: 2 with bullets and the rest are empty. What is probability you'll get one with bullet?

Answer 2

There remain $4$ empty chambers and $2$ with bullets. Probability that you die is $\frac{1}{3}$.