If I have the following model function for sun radiance through a day,
$$ P(h) = 0.3 \pi \sin(\frac{h\cdot\pi}{12}-\frac{7\pi}{12}) [\frac{kWh}{m^2}] $$
Where $h$ is the hour of the day and the variable I don't know how to treat it. The solutions fits if I set my calculator in radians instead of degrees but I can't comprehend why.
Thanks in advance.
Note that the sine function argument increases by $2\pi$ when $h$ increases by $24$ hours, so that is one cycle. This means you should use radians.