Show that if five points are placed in a Equilateral triangle with sides of 2, two points will always be closer than 1

542 Views Asked by At

I don't know where to start.

i know that I am supposed to use some sort of probability principal.

1

There are 1 best solutions below

2
On
  • Try to divide an equilateral triangle into four equal parts, each of which is an equilateral triangle of side $1$.

  • Now, if there are five points, then two of these must lie within the same equilateral triangle, since we have five points, which is more than four triangles.

  • Prove that any two points within an equilateral triangle of side $1$ cannot be separated by more than $1$ unit. Then you would be done.