Find that the circle has four vertices.
$$\gamma (t)=\langle R\cos (t/R), R \sin (t/R)\rangle$$ for $t\in [0,2\pi]$
I know the theorem:
Every simple closed convex curve has atleast four vertices.
Find that the circle has four vertices.
$$\gamma (t)=\langle R\cos (t/R), R \sin (t/R)\rangle$$ for $t\in [0,2\pi]$
I know the theorem:
Every simple closed convex curve has atleast four vertices.
Copyright © 2021 JogjaFile Inc.
We've been through similar things with you before. A vertex is a critical point of the curvature of a plane curve. Since the curvature of a circle is constant, every point of a circle is a vertex.