To elaborate on copper.hats comment, if $\mathbb P(X>10)>0$ then there exists some integer $m$ such that $\mathbb P\left(X>10+\frac1m\right)$. But this implies that $\mathbb P\left(|X-X_m|\geqslant \frac1m\right)$, and contradicting the assumption that
$$
\lim_{n\to\infty}P\left(|X-X_n|\geqslant \frac1n\right) = 0.
$$
To elaborate on copper.hats comment, if $\mathbb P(X>10)>0$ then there exists some integer $m$ such that $\mathbb P\left(X>10+\frac1m\right)$. But this implies that $\mathbb P\left(|X-X_m|\geqslant \frac1m\right)$, and contradicting the assumption that $$ \lim_{n\to\infty}P\left(|X-X_n|\geqslant \frac1n\right) = 0. $$