This sounds odd but, there was a math question in my textbook which intrigued me. So it goes ‘Sarah puts $200 in her account every month, which is subject to 1% interest. Show the value of money in her account after x months’. So I assumed that you’d need to use the sigma notation in order to reduce using … . This might be a really odd question but does anyone know the answer of how to represent this formula?
$$x_{n+1}=1.01(x_n+200)$$ $$x_1=0$$ $$x_n$$ represents how much was in the account on the nth month prior to placing the $200 in the account on that month.
x represents the value of money in the bank. Essentially, I’m asking whether there is a simplified method of finding the value of money after y months
In Month $x=1$, The Account value $A_1$ is $200$.
In Month $x=2$, she puts in an extra $200$, and gets $1\%$ interest on what she already had, so $A_2=402$.
Then it follows $A_{n+1}=1.01(A_n)+200$
What we have here is a recurrence relation. We need to find a closed form from this. $$A_1=200$$
$$A_2=1.01(200)+200$$ $$A_3=1.01(1.01(200)+200)+200)=1.01^2(200)+1.01(200)+200$$ $$A_4=1.01(1.01^2(200)+1.01(200)+(200))+200$$ $$A_4=1.01^3(200)+1.01^2(200)+1.01(200)+200$$
Note that $A_1=200$ and the pattern is easily spotted: $$A_n=200\sum_{k=0}^{n-1}{[(1.01)^k]}$$
Sum notation is indeed required as suggested in your question.