$ABC$ and $ADB$ are similar isosceles triangles, such that $BC: CD = x : y$
I am told that the area of $ABC$ : area of $ADB$ = $x$ : $x + y$, but I cannot see intuitively why this would be the case?
Any help would be appreciated.
2026-04-11 14:50:40.1775919040
Similar isosceles triangles
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Draw a perpendicular from $A$ onto $BD$ and note that it also serves as a perpendicular for the other triangle.