In $\triangle ABC$, $AB=8, BC=7, CA=6$, and side $BC$ is extended to point $P$, so that $\triangle PAB$ is similar to $\triangle PCA$. Find the length of $PC$.
2026-05-05 07:47:47.1777967267
Similar Triangles with proportions
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Corresponding sides tell you $\frac {AB}{AC}=\frac {PB}{PA}=\frac 43=\frac {7+PC}{PA}=\frac{PA}{PC}$