Given some triangle ABC, with feet of altitudes D, E, and F, I need to show that triangle ABC is similiar to triangle AEF. This is an image I made for it
I have been able to show that the angles of ABC are combinations of either 1, 2, or 3 (by similiar triangles), and that 1 + 2 + 3 is 90 degrees. This triangle is also supposed to be acute. I have been stuck on this for a while. Any help in the right direction would be greatly appreciated
EFBC is a circular quadrilateral since CFB=BFC=right angle. Thus AEF=B,AFB=C, A=A.Thus similarity follows.