Simple Triangle Question

Question

I'm looking to solve for the length of side X in the diagram above. Trying to design this enclosure but having difficulty with the math. I know it's simple triangle math that I'm forgetting, but any help would be appreciated! The depth of the side panels isn't decided yet, but if it is important to solving, let me know.

Answer 1

A little trig does it: on the side view, from the top of slanted section draw a vertical line down, and from the bottom of slant draw a horizontal to the right. You get a triangle with the top angle $\theta = 180-135 = 45$ degrees. The height of the slanted section is then $z=10 \cos\theta = \frac{10}{\sqrt{2}} \approx 7.071''$.

Then $x\approx 36.25-1.125-7.071 \approx 2' 4.054''$.

Answer 2

If we assume, that in the front view picture the angle between sloped $10''$ side and side $x$ is $135^{\circ}$, as on the side view, then $$x=3'0.25''-1.125''-5\sqrt{2}''\approx2'4.054'' $$