If I have the following function: AB + 'B , using karnaugh it is simplified to A +'B
What I want is to make this simplification using boolean algebra. What law is used in boolean algebra to transform AB + 'B to A + 'B?
Thanks for the help
2026-03-25 11:23:41.1774437821
Simply AB + ′B using boolean algebra
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I suppose you can justify the steps below. \begin{align} AB+B' &= AB + (A+A')B'\\ &= AB + AB' +A'B'\\ &=(AB + AB') + (AB'+A'B')\\ &= A(B+B') + (A+A')B'\\ &= \cdots \end{align} (Can you take it from here?)