I'm trying to find which kind of singularity this function has;
$$f(z) = \sin\left(\frac 1 {z-1}\right)$$
by using Laurent Series in a circle-area around $z=1$. Now usually the question is focused around $z=0$, so that I can use maclaurin series for the sinus function, but in this case I don't know how to solve it.