Sketching graph Exponential and logarithmic functions.

Question

Sketch the graph of each of the following (labelling asymptotes), and state the range of each: $y=3^x+1$
is below graph. I have no idea, how can it get $(0,2)$ i know that the $+1$ is asymptotes, Isn't it $(0,2)$ suppose to be $(0,3) $accroding to the equation.

Appreciate your explaination! thanks

Answer 1

yes, the graph plotted above is correct because
$y=3^x+1$, $x=0$
$y=3^0+1$
$y=1+1$
$y=2$ when $x=0$
so, the graph plotted it correct!