Smallest overlapping circles containing unit circles in each section - Fourth arrangement

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I hope people aren't too tired of these. I'm finding them to be really lovely.

This question is closely related to a question that I posted recently.

Another way of overlapping 3 circles looks like this:

enter image description here

If we want to size these circles such that they are as small as possible yet still large enough for a unit circle to fit in each of the 7 regions, then we get a diagram like this:

enter image description here

The question then, is what are the radii of the circles?

In contrast to my previous posts... I have a proposed answer! But the exact answer is sufficiently inelegant that it has me wondering whether I got it right. My explanation is shown below.

The smaller circle in the middle has radius A. The other two circles have radius B.

enter image description here

  1. EDIT FALSE: The red triangle must be a right triangle with legs B and hypotenuse $\sqrt{2}B$.
  2. We can also say that the red hypotenuse has length 2B - 2(A-2).
  3. The blue triangle gives us a right triangle using both A & B.

So we get these 2 equations:

  • $\sqrt{2}B=2B-2(A-2)$
  • $(B-1)^2=(A+1)^2+({\sqrt{2}\over2}B)^2$

Solving these equations gives exact answers that appear inelegant to me. So I question the result. But... the approximate answers are reasonably close to what I got just constructing the diagram. So perhaps the smaller circle, A, really is ${\sqrt{52\sqrt{2}+86}\over{2}}-{\sqrt{26\sqrt{2}+43}\over{2}}+{2\sqrt{2}}+{1\over2}≈5.178$

Confirmation that this seems valid or correction where it's not valid would be much appreciated.