Is there a way to solve this equation by hand?
$\exp(x)(5-x)=5$
Solutions:
$x_1=0$
$x_2= 4.96511$
There is no elementary solution.
You can use the Lambert W-function. This is the inverse of $f(z)=ze^z$.
Substitute in $y=x-5$ to get $e^{y+5}\times -y = 5$. This becomes $e^{y}y = -5e^{-5}$.
We have $y=W_{-1}(-5e^{-5})=-5$ or $y=W_{0}(-5e^{-5})\approx-0.03488$.
Hence $x=0$ or $x\approx4.96511$.
You will need a special calculator to compute the second one.
Alternatively, you can approximate the second solution by a numerical solution, like Newton-Raphson.
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There is no elementary solution.
You can use the Lambert W-function. This is the inverse of $f(z)=ze^z$.
Substitute in $y=x-5$ to get $e^{y+5}\times -y = 5$. This becomes $e^{y}y = -5e^{-5}$.
We have $y=W_{-1}(-5e^{-5})=-5$ or $y=W_{0}(-5e^{-5})\approx-0.03488$.
Hence $x=0$ or $x\approx4.96511$.
You will need a special calculator to compute the second one.
Alternatively, you can approximate the second solution by a numerical solution, like Newton-Raphson.