solve for x and y in terms of u and v. Then compute the Jacobian
let: $u = x+y$ and $v = x-y$
since:
$$\frac{\partial (x,y)}{\partial(u,v)}* \frac{\partial (u,v)}{\partial(x,y)} = 1$$
but
$$\frac{\partial (u,v)}{\partial(x,y)} = -2$$
hence the jacobian is $$\frac{\partial (x,y)}{\partial(u,v)} = -\frac{1}{2}$$
but I don't know how to solve for x and y in terms of u and v
Adding and respectively, subtracting the two equations $u=x+y$ and $v=x-y$, we get $u+v=2x$, $u-v=2y$. Thus $x=\frac{u+v}{2}$ and $y=\frac{u-v}{2}$.