Solve the Equation in real/Complex numbers:
Solve $$\left(\sqrt{\sqrt{2}-4-x}\right)+x^{\frac{1}{4}}=2^{\frac{-1}{4}}$$
My try:
Letting $x=t^4$ we get
We get
$$\left(\sqrt{\sqrt{2}-4-t^4}\right)+|t|=2^{\frac{-1}{4}}$$
Then:
$$\left(\sqrt{\sqrt{2}-4-t^4}\right)=2^{\frac{-1}{4}}-|t|$$
Squaring we get:
$$\sqrt{2}-4-t^4=t^2+\frac{1}{\sqrt{2}}-|t|2^{\frac{3}{4}}$$
$\implies$
we get
$$t^4+t^2+4=\frac{1}{\sqrt{2}}+|t|2^{\frac{3}{4}}$$
Any clue here?
One solution is given by $$x=\frac{1}{16} \left(8 \sqrt{2}-56\right)+\frac{1}{2} \sqrt{-5-\frac{14 \sqrt{2}}{3}+\frac{713}{3 \sqrt[3]{16569-3994 \sqrt{2}+2 i \sqrt{40035168-28289088 \sqrt{2}}}}-\frac{52 \sqrt{2}}{\sqrt[3]{16569-3994 \sqrt{2}+2 i \sqrt{40035168-28289088 \sqrt{2}}}}+\frac{1}{3} \sqrt[3]{16569-3994 \sqrt{2}+2 i \sqrt{40035168-28289088 \sqrt{2}}}}-\frac{1}{2} \sqrt{5+\frac{14 \sqrt{2}}{3}+\frac{3}{64} \left(56-8 \sqrt{2}\right)^2+\frac{1}{2} \left(56 \sqrt{2}-336\right)-\frac{713}{3 \sqrt[3]{16569-3994 \sqrt{2}+2 i \sqrt{40035168-28289088 \sqrt{2}}}}+\frac{52 \sqrt{2}}{\sqrt[3]{16569-3994 \sqrt{2}+2 i \sqrt{40035168-28289088 \sqrt{2}}}}-\frac{1}{3} \sqrt[3]{16569-3994 \sqrt{2}+2 i \sqrt{40035168-28289088 \sqrt{2}}}+\frac{\frac{1}{4} \left(56-8 \sqrt{2}\right) \left(336-56 \sqrt{2}-\frac{1}{16} \left(56-8 \sqrt{2}\right)^2\right)-2 \left(924-228 \sqrt{2}\right)}{4 \sqrt{-5-\frac{14 \sqrt{2}}{3}+\frac{713}{3 \sqrt[3]{16569-3994 \sqrt{2}+2 i \sqrt{40035168-28289088 \sqrt{2}}}}-\frac{52 \sqrt{2}}{\sqrt[3]{16569-3994 \sqrt{2}+2 i \sqrt{40035168-28289088 \sqrt{2}}}}+\frac{1}{3} \sqrt[3]{16569-3994 \sqrt{2}+2 i \sqrt{40035168-28289088 \sqrt{2}}}}}}$$