solve the following equation for x $(x^2-8x-3)÷(8x-3)=(x^2+4x+4)÷(4x+4)$
The problem here I am encountering with is figuring out which method to be used here for solving. I am not getting how to start with. Hope I will get good hint.
2026-02-23 03:22:24.1771816944
Solve the equation for x.
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You could just "cross multiply" so to speak. Then you get a cubic equation on both sides. Combine like terms, gathering them all on the same side of the equation, and solve for $x$.
To clarify what I mean by "cross multiply:" if you have $$\frac ab = \frac cd$$"cross multiplying" means you multiply both sides by the product of denominators. This gives you $ad = bc$.