Solve this quadratic function $h = -0.0625t^2 + 3t - 20$

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In a science experiment, a student is studying the relationship between the temperature and the growth of a plant. She develops the following quadratic model: $h = -0.0625t^2 + 3t - 20$, where h is the height of the plant, in cm, and t is the growing temperature, in °C.

  • Determine the temperatures that result in a plant height of zero.

  • Use your result from part a) to find the temperature that will maximize the height of the plant.

  • Use the equation to determine the height of the plant grown at a temperature of $5$ °C. Comment on the domain of the mathematical model.

  • Use your results above to construct a graph for this relation.

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1. Temperatures that result in zero height:

In this case, let $h=0$ and solve the quadratic equation for $t$.

We have: $$0=-0.0625t^2+3t-20$$

Multiply both sides by $-16$ to get:$$0=t^2-48t+320$$

And then you could factor and solve:

$$0=t^2-48t+320$$ $$0=(t-40)(t-8)$$

Now, we know that $0=t-40$ or $0=t-8$, so $t = 8, 40$.

So, the plant will have zero height at $8$ and $40$ degrees.

2. Temperature that maximizes plant height:

All you need to do is find where the vertex of the equation $h=-0.0625t^2+3t-20$ is when you graph it.

The $t$-value of the vertex will be the average of the two solutions you found to part 1.

3. Height at $5$ degrees C:

Plug in $5$ for $t$ into the model and simplify.

$h=-0.0625(5)^2+3(5)-20$

(the rest is just numerical calculations)

4. Graph:

I can't really help you with this one, but you should find that the graph is an upside-down "U" shape.