solving differential equations by drawing phase diagrams: The Romer growth model

77 Views Asked by At

In this book by Buyse (based on Shone) (see picture, I don't get how the author derives the slope of the line g_overdotK(t) = 0 and the slope of the line $g_overdotA(t)=0$.

It seems like the text bounces back and forth between the 'dynamics of the growth rate', e.g. g_overdotA(t)/gA(t) and just the time derivative of the growth rate, namely g_overdotA(t), and uses both interchangeably.

Anyway, by taking the derivative and setting it equal to zero, of the dynamic equation, I get (1-omega)/beta for the slope (nor the 1 result of the other equation). But I don't get why you can work with g_overdotA(t)/gA(t) instead of g_overdotA(t).

What I'm I missing here? Thanks!

enter image description here) enter image description here