Did I solve the following quadratic equation correctly.
$$W(W+2)-7=2W(W-3)$$
I got.
$$W^2-8W+7$$ Then for my solution I got.
$$(W-1)(W-7)$$
2026-04-30 03:58:20.1777521500
Solving the quadratic equation $W(W+2)-7=2W(W-3)$
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$$W(W+2)-7=2W(W-3)$$
$$\Downarrow$$
$$W^2+2W-7=2W^2-6W$$
$$\Downarrow$$
$$W^2-8W+7=0$$
$$\Downarrow$$
$$(W-1)(W-7)=0$$
You're right, well done. The solutions are $W=7$ and $W=1$.
EDIT: It should be written as I showed above, you've omitted "$=0$" part of the equation, intentionally or unintentionally.