$\mathbf{Q}$: We consider a standard form linear programming problem, where $\mathbf{A} \in {\mathbb{R}^{mxn}, \mathbf{c} \in \mathbb{R^{n}}, \mathbf{b} \in \mathbb{R^{m}} }$ and the decision variable $\mathbf{x}$ is in $\mathbb{R}^n$. Prove or disprove:
If there are several optimal solutions, then the set of optimal solutions lies in the convex hull of all the basic feasible solutions.
$\mathbf{My }$ $\mathbf{answer}$:True.
I chose this answer as it was the most intuitive answer and thought of proving by contradiction, but unfortunately I am unsure of how I can go about proving this. Some help will be deeply appreciated.
You haven't told us what your standard form is. I'll assume that it's
$\min c^{T}x$
$Ax=b$
$x \geq 0$
This is false, for the simple reason that you can have an unbounded set of optimal solutions that cannot be the convex hull of a finite set of points.
For example, try
$\min x_{1}-x_{2}$
$x_{1}-x_{2}=0$
$x \geq 0$
Here, the only BFS is $x=0$, but there are many other optimal solutions such as $x_{1}=1$, $x_{2}=1$.