I got really stuck proving this exercice of my text on geometry. Can anyone provide a solution please?
If the lines $AA'$, $BB'$, $CC'$ concur, then the points of intersection of the lines:
$AB,A'B'$; $BC,B'C'$; $CA,C'A'$; $A'B,BA'$; $B'C,BC'$; $C'A,AC'$ lie by thirds on 4 separated lines
Here's a picture of the initial situation:
I really tried everything on my text and did lots of sketches but failed.
Please, help.