Sum of Areas Geometry Problem. Cannot understand how provided answer is derived.

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Given that $CH=8$, $HI=3$, $DC=10$, and $FG=9$, I have to find the area of parallelogram $DEFJ$.

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I'm really stuck here. I have tried assigning coordinates to each vertex, and I have tried to use similar polygon ratios. My teacher says the answer is $122$, but I do not know how it is possible to get that answer. Any tips or solutions would be greatly appreciated. Thank you so much in advance!

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Here is a version that is to scale. Moving the point $J$ will result in different areas of the parallelogram (as pointed out by StAKmod). I think your problem is not well defined.

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