if I have a mean \begin{equation} \langle (a+b)^2 \rangle \end{equation} is this then equal to \begin{equation} \frac{1}{T} \int\limits_{0}^{t} a^2 + \frac{1}{T} \int\limits_{0}^{t} 2ab + \frac{1}{T} \int\limits_{0}^{t} b^2 \end{equation} because of the sum rule for integrals?
2026-03-16 12:08:31.1773662911
sum rule for integrals in mean
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