Summation of harmonic series.

728 Views Asked by At

I'm trying to figure out how to answer this linear algebra question and can't figure it out. Can someone please explain it to me?

Thanks a bunch!

Here's the questions:

enter image description here

1

There are 1 best solutions below

0
On BEST ANSWER

To do this consider the integral $$\int_{1}^{x}\frac{1}{t}dt.$$ We can approximate it from below and from above using lower and upper Riemann sums for the partition that cuts at the integers $1,2,3,...$.

Since $\frac{1}{t}$ is decreasing the lower and upper Riemann sums are obtained when the function is evaluated at the right boundary and the left boundary of the intervals of the partition.

We get $$\sum_{n=1}^{m} \frac{1}{n}=\sum_{n=1}^{m} \frac{1}{n}(n+1-n)>\int_{1}^{x}\frac{1}{t}dt=\ln(x)>\sum_{n=1}^{m} \frac{1}{n+1}(n+1-n)=\sum_{n=1}^{m}\frac{1}{n+1}$$