Surface area of inverse functions

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I was wondering if the area of a curve rotated about the x-axis could be found by rotating the inverse curve about the y-axis because I have to find the the area by rotating $x = \frac{1}{4} y^2 - \frac{1}{2} \ln(y)$

and it seems like this would be much easier to do about the y-axis because than I don't have to find $y(x)$. Is this a correct way of solving this?