I’m having a hard time determining if this sentence would be a tautology or an open sentence.
x is a multiple of 7 or x is not a multiple of 7.
I’m not sure if this would be a tautology because of the free variable x. For example, the sentence “x is a multiple of 7.” would be an open sentence and therefore not have a truth value. “x is not a multiple of 7” would also be an open sentence and therefore not have a truth table. Therefore I don’t see the sentence shown as a tautology, I see it as an open sentence. If the statement was:
$(\forall x \in \mathbb{R})$ (x is a multiple of 7 or x is not a multiple of 7)
I would see this as a tautology because x was is bounded by the quantifier $\forall$. Can someone explain if I’m wrong? Thank you!
Everybody agrees that
A ∨ ¬Ais a tautology, but in the context of first-order logic only some authors also call∀x (Ax ∨ ¬Ax)a tautology. For clarity, we can always say that the latter is a first-order validity but not a propositional-logic tautology.This open formula (i.e., not a sentence, due to the free variable) can be formalised as
P or not P, so it is a propositional-logic tautology, so it is also a validity.Being atomic, it indeed does not make sense for the validities
x=x(an open formula) and0=0(a sentence) to be propositional-logic tautologies.The open formula
A(x) or not A(x)is valid, i.e., logically true. So, the sentence∀x∈R (x is a multiple of 7 or x is not a multiple of 7)is also valid; but it is not a propositional-logic tautology, since in propositional logic it is atomic.