Taylor series derivative values

43 Views Asked by At

Suppose

$$f(x) = 1 + x + x^2/2^2 + x^3/3^2 + … + x^k/k^2 + \cdots $$

What is the value of $f(0)$? $1$

What is the value of $f'(0)$ ? $1$

What is the value of $f''(0)$ ? $1/2$

What is the value of $f'''(0)$ ? $1/3$

However my answer for $f'''(0)$ is wrong. I don't understand why

1

There are 1 best solutions below

0
On BEST ANSWER

$$\frac{1}{3^2}=\frac{1}{3!}f'''(0)$$

Multiply both sides by $3!$.