I am working through Applied Analysis by John K. Hunter. Problem 2.7 states:
Prove that the set of Lipschitz continuous functions on $[0, 1]$ with Lipschitz constant less than one and zero integral is compact in $C([0, 1])$.
What does "less than one and zero integral" mean? $|C|<1$? $0\leq C\leq 1$?
I interpret that to mean the constant is less than one, and also the integral of the function from zero to one is zero. There should be a comma there, that would help.