If it can be assumed that the number of submissions per minute interval is Poisson distributed, calculate the probability that
(a) at least two jobs will be submitted in any minute
$P(X\geq 2)$ so $1-(P(x=0) + P(x=1) + P(x=2)) = 0.7618967$
(b) no job will be submitted in any minute
$P(x=0)$ so $((e^{-4})\cdot (4^0))/0! = 0.018315$
(c) not more than one job will be submitted in any one-minute interval.
$P(X\leq 1)$ so $(P(x=0) + P(x=1))$
Please let me know if my answer/way of approaching the problem is right. Thank you.