Say $f(x)= \sqrt{2x + 2}$ Domain here would be limited to values of $x$ greater than or equal to $-1$. $g(x)=(2x^2)+3$ (arbitrary, really) $g(f(x))$ would have no restrictions on domain despite $f(x)$ having restrictions, right?
Thanks
2026-04-29 19:05:43.1777489543
The Composition of Functions
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That's not correct.
First of all, Domain of $f$ consists of $x \geq -1$. $g\circ f$ will also have this domain restriction, as plugging any number less than $-1$ in $f$ doesn't make sense.