The generalized Laguerre polynomials has the form:
$L_n^m(x):=\dfrac{x^{-m}e^x}{n!}\dfrac{\mathrm{d}^n}{\mathrm{d}x^n}(e^{-x}x^{n+m})$
My question is, what will be the $n^{th}$ order derivative when $L_n^m(x)$ is changed to $L_n^m(q^2)$?
The generalized Laguerre polynomials has the form:
$L_n^m(x):=\dfrac{x^{-m}e^x}{n!}\dfrac{\mathrm{d}^n}{\mathrm{d}x^n}(e^{-x}x^{n+m})$
My question is, what will be the $n^{th}$ order derivative when $L_n^m(x)$ is changed to $L_n^m(q^2)$?
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