The geometric distribution - How many trials occur before we obtain a success doubt

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I have doubts on the same question

First, What is k here?

Second, I know E[X]= E[I{A}], I define indicator random variable. We can say that I{A} is the indicator random variable of geometric distribution. Now, I{A} depend upon probability of success and failure. So I{A} = 1.pr{Success} + 0. pr{failure}. However, from the 1st line of derivation I cannot understand where 1.pr{Success} + 0. pr{failure} is used.

3rd, from where we appear in the 3rd line of the calculation?

if it is coming from geometric summation then the geometric summation for infinite series is

$$\displaystyle\sum\limits_{k=0}^\infty x^k = \left(\frac{1}{1-x}\right)$$

Then It should be $$\left(\frac{p}{q}\right)\left(\frac{1}{1-q}\right)$$