These sets are presented in lists of element form. Write the sets in the form of the set generator
a) {0,3,6,9,12}
b) {-3,-2,-1,0,1,2,3}
So... would the solutions be:
a) {n*3: n=0,1,2,3,4}
b) {n:n ∈ Z}
These sets are presented in lists of element form. Write the sets in the form of the set generator
a) {0,3,6,9,12}
b) {-3,-2,-1,0,1,2,3}
So... would the solutions be:
a) {n*3: n=0,1,2,3,4}
b) {n:n ∈ Z}
That's not a very specific prompt, is it? There are so many options.
a. $\{n \in \mathbb N \mid n \le 12,\ 3|n \}$
b. $\{ x-1 \mid x \in \{-2,-1,0,1,2,3,4\}\}$
If you wanted to get really picky, you could just say a. $\{n \mid n \in \{0,3,6,9,12\}\}$ or similar. Your answer (in your question) to part a. is correct, but b. is not. $\mathbb Z$ contains all integers, which that set from part b. certainly does not.