Suppose someone hands you a series where the terms are some function of x and your goal is to find some bounds for the series for a given set of x-values (I'm thinking of power series in particular). What tools do you use to find these bounds? In particular, could you tell whether a power series in x is unbounded as x goes to infinity? I lack formal training in analysis, but please do not restrain your answers because of that.
For example, consider $$f(x) = \sum_{n=0}^\infty \frac{(-x)^n}{n!}$$ and for the moment do your best to forget that this is $\exp(-x)$. Let's say we looked at x = 100 and looked at the first terms of the series, we'd see some terms of rather large magnitude: $$f(100) = 1-100+5000-500000/3+... $$
The series is absolutely convergent, and the magnitude of terms eventually decreases. But how would one quickly tell that these large magnitude terms - after well over 100 such terms - would so perfectly cancel to leave a number less than 1? In the language of my question at top, how could one tell that $0 \leq f(x) \leq 1$ for $x \geq 0$?
Here's my attempt to show this particular series is between 0 and 1 for $x\geq0$: Consider $$g(x) = \sum_{m=0}^\infty \frac{(x)^m}{m!}$$ Note that $g(x)$ is unbounded as x grows larger, and in particular that $g(x)\geq 1$ for $x\geq 0$. Noting $$g(x) f(x) = \sum_{n=0}^\infty \sum_{m=0}^\infty \frac{(-1)^n x^{n+m}}{n!m!},$$ we see that on changing indices to $q=n+m$ we have $$g(x) f(x) = \sum_{q=0}^\infty \sum_{n=0}^q \frac{(-1)^n x^{q}}{n!(q-n)!}.$$ Thus $$g(x) f(x) = \sum_{q=0}^\infty \frac{x^q}{q!} \sum_{n=0}^q (-1)^n \binom{q}{n},$$ which simplifies to $$g(x) f(x) = \sum_{q=0}^\infty \frac{x^q}{q!} \delta_{q 0} = 1.$$
Thus $$f(x) = \frac{1}{g(x)},$$ and since $g(x)\geq 1$ for $x\geq 0$, we see that $$0 \leq f(x) \leq 1 $$ for $x\geq 0$.
This attempt to put bounds on f(x) for $x \in [0,\infty) $ is to demonstrate my thought process on putting bounds on power series (the technique I used rested solely on foreknowledge), and I look forward to reading about the tools you use to put bounds on more general power series.
I'll open with one of the main analytical tools used, the comparison test. This is particularly useful for answering the 'bounded or unbounded' question.
Suppose $A = \sum_{i=1}^{\infty}a_{n}$ and $B = \sum_{i=1}^{\infty}b_{n}$ are series. If $a_{n} \leq b_{n}$ for all $n \in \mathbb{N}$ and we know that B is bounded, then A is bounded. Similarly, if we knew that A was unbounded, we would know that B must be unbounded.
For example, if we begin with the knowledge that $\sum_{i=1}^{\infty}\frac{1}{n}$ is unbounded, we can say that $\sum_{i=1}^{\infty}\frac{3}{n}$ is unbounded, as each term is greater than a known unbounded series. Similarly since $\sum_{i=1}^{\infty}\frac{1}{n^{2}}$ is bounded, we know that $\sum_{i=1}^{\infty}\frac{1}{4n^{2}}$ is bounded, as each term is smaller than that of the former series.
It's been a long time since I've done much analysis, there are a great many tools that other posters can hopefully explain better but I hope that's an interesting idea to get you started.