$O$ is the center of the circle , $A$ and $B$ lie on the circle
what are the possible values of $x$ and $y$

I found answers options , asked to mark one or more
A) X = 80 Degree AND Y = 50 Degree
B) X = 50 Degree AND Y = 80 Degree
C) X = 450 Degree AND Y = 90 Degree
D) X = 700 Degree AND Y = 30 Degree
E) X = 60 Degree AND Y = 60 Degree
We know
$(1)$: the sum of the angles equals $180^\circ$.
$(2)$: Two sides of $\triangle AOB$, namely $\overline{OA}, \overline{OB}$ have equal length. Why? Because $\;|\overline{OA}| = |\overline{OB}| = r$, the length of the radius of the circle.
So from $(2)$ we know that $\triangle AOB$ is an isosceles triangle, and that the angles opposite sides $\overline{OA}, \overline{OB}$ are necessarily equal in measure. This means that the unmarked angle has measure equal to $x$.
From $(1):$ Summing the angles gives us $\;x + x + y = 2x + y = 180\tag{3}$
(Note, for the very large x values which are greater than $180$, we can compute their equivalent angles by subtracting $180$ from $x$ until $x' \lt 180$. Then evaluate $(3)$ using $x', y$. It turns out that in both cases where the given $x > 180$, the resulting $x'$s with corresponding y values fails to satisfy $(3)$