Triangle side-length problem

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my problem is the following.

A triangle ABC is given. P is a point on $\overline{AB}$. $k_1, k_2, k$ are the radii of the in-circles of APC, BPC, ABC. $s_1, s_2, s$ are radii of the ex-circles of these triangles which are lying at the angle ACB.

Show that \begin{equation} \frac{k_1}{s_1} \cdot \frac{k_2}{s_2} = \frac{k}{s} \end{equation}

Hope you can help me.

Thanks.