I saw an equation on my book which replaced $\tan (B/2)$ with $\sqrt{ s(s - b) /(s - a) (s - c) }$
How are they related?
2026-03-29 13:21:42.1774790502
Triangles' relation to Tangent
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May be you meant this:
$$ {\displaystyle \displaystyle \tan \left({\frac {B}{2}}\right)={\sin({\frac {B}{2}}) \over \cos({\frac {B}{2}})}={\sqrt {{(s-c)(s-a)} \over {s(s-b)}}}} $$
A trig ratio cannot equal area of the triangle! Please see the book carefully.