$\sin (A) = \sin 3x$ is equivalent to $\sin(A) = 3 \sin(x) - 4\sin^3(x)$, then $-\cos 3x$ is $-4\cos^3x + 3\cos$.
is that correct? I just want to make sure I'm distributing the negative sign correctly.
2026-03-25 09:44:46.1774431886
Trigonometry equivalent
41 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail AtRelated Questions in GEOMETRY
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