Let $S^1=\{z \in \Bbb C : |z|=1\}$. Let $f$ be any continuous function from $S^1 \to \Bbb R$. Then:
A. $f$ is bounded
B. $f$ is uniformly continuous
C. $f$ has image containing a non-empty open subset of $\Bbb R$
D. $f$ has a point $z \in S^1$ such that $f(z)=f(-z)$.
Since $S^1$ is compact and connected, we get $\text {Image}(f)$ to be a closed & bounded interval so option A & C are true.
Option B seems to be true because $f$ is continuous on a compact set $S^1$.
Also option D is just Borsuk-Ulam theorem.
Where have I gone wrong?
C is wrong as $f$ might be constant.