So here we split the equation in 2 parts
- The leading coefficient
- The rest of the equation
Suppose we have an equation $$ax⁴+bx³+cx²+dx+e=0$$ $$\implies bx³+cx²+dx+e= -ax^4$$
Now we plot the graph of LHS and RHS, that is, $bx³+cx²+dx+e$ and $-ax^4$.
The $x$ coordinate of point where these graphs intersect each other is the solution for the given equation.
By this way, we can find the intervals of the solutions by using the techniques of differential calculus.
Following is an example to make the things more clear:
https://acrobat.adobe.com/link/track?uri=urn:aaid:scds:US:06df1c73-5e8c-48ff-993e-2728e5ec1997
Thanks for reading, have a good day!