Trying to understand part of derivation of divergence in curvilinear coordinates

177 Views Asked by At

I'm trying to understand how the divergence formula in curvilinear coordinates is derived, but unfortunately my textbook doesn't go into much detail. Here is what they show:

I was wondering if someone could answer a couple of questions for me?

Firstly, is the vector field assumed to be constant?

Secondly, how exactly do they get to the line (8.9)? I don't really understand it. Is it done using surface integrals or something simpler?

If someone can answer these questions for me I would really appreciate it!

1

There are 1 best solutions below

6
On BEST ANSWER

The flux through the left face of the "curvi-cube" is approximately $(A_1h_2h_3dx^2dx^3)|_{(x^1,x^2,x^3)}$ (assuming $A_1$ doesn't change much along the surface spanned by $h_2dx^2, h_3dx^3$, or more specifically, that how $A_1$ changes over the surface doesn't change much from the left to the right face, so we may as well pick a corner to evaluate it), while the flux through the right face is $(A_1h_2h_3dx^2dx^3)|_{(x^1 + dx^1,x^2,x^3)}$. Thus the net flux out if the cube through those two faces is $$ (A_1h_2h_3dx^2dx^3)|_{(x^1 + dx^1,x^2,x^3)} - (A_1h_2h_3dx^2dx^3)|_{(x^1,x^2,x^3)} $$ Since $dx^2$ and $dx^3$ doesn't change between the two faces, we may factor them out. This gives the left-hand side.

As for the right-hand side, we multiply by $1 = \frac{dx^1}{dx^1}$, and note that $\frac{1}{dx^1}$ goes together with the bracket to form the definition of the partial derivative of $A_1h_2h_3$ with respect to $x^1$. The remaining factor $dx^1dx^2dx^3$ stays outside the derivative.