Understanding sampling from a normal distribution with zero mean

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I'm studying probability. I came a cross "sampling from distributions". Given a probability density function $f_X(x)$, what I understood is that sampling means getting values of $x$ according to the distribution of probabilities over the $x$s. So that a value of $x$ (or an interval of $x$) that has a probability mass or density more than others will have a higher chance to appear in the sampling than others.

I have three questions here:

1- is my previous understanding correct?

2- I often see people sample from a normal distribution with zero mean and variance of 1. Why is that?

3- Does sampling from a normal distribution with zero mean and variance of 1 means that the chance of getting zeros or numbers around zero is higher than other numbers?

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Yes your understanding is correct, although for continuous distributions every exact number has probability $0$, which is almost a paradox, but people get around this by talking about the probability of a sample being in a set like an interval, which has positive probability. The normal distribution $N(0,1)$ can be used to generate samples from any Gaussian distribution $N(\mu, \sigma)$ and even higher dimensional Gaussian distributions, so it's sort of a "building block" distribution for sampling from other distributions. The normal distribution is monotonically decreasing as you move away from zero, so yes, numbers closer to zero are more likely than numbers farther away from zero.

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The Normal distribution is exactly the same thing as a Gaussian distribution, there are just two names.

People use a lot the normal distribution because of the Central Limit Theorem : it states that the sample mean of an independent and identically distributed sample converges in distribution to a normal distribution. This is true whatever the original distribution of the random sample.

Thus the normal distribution is usually appropriated to model the noise. If the sample is big enough, there is a good chance that the noise will follow a normal distribution. Furthermore, the normal distribution is symmetric (e.g. you wouldn't use a Gamma or Chi square distribution for the noise, since they only take positive values).