Consider the differential equation
$$f^{iv}+3f^{''}-f=g$$
I have read that taking the Fourier Transform of both sides gives $$\left(i\lambda\right)^{4}F\left(\lambda\right)+3\left(i\lambda\right)^2F\left(\lambda\right)=G\left(\lambda\right)-F\left(\lambda\right)=G\left(\lambda\right)$$
Im not sure how they have done this. I think it involves using $\mathcal{F}\left[f^{'}\right]=i\lambda\mathcal{F}\left[f\right]$ but I don't know how.
You can combine
First use 1) to separate each term. Then use 2) as many times you need to get down to $F[f]$ for each individual term.