I am looking from : http://en.wikipedia.org/wiki/Lipschitz_continuity
Continuously differentiable $\subseteq$ Lipschitz continuous $\subseteq$ α-Hölder continuous $\subseteq$ uniformly continuous $\subseteq$ continuous.
What I am seeking is a precise definition of it. Intuitively, it is like I have a pointed pencil and any curve I can draw w/o lifting the pencil from the paper is continuous. BUT, what I ask is how that really boils down to the the $|f(x +\epsilon) - f(x)| < \delta $. Obviously this $\epsilon,\delta$ definition implies continuity, but is the opposite also implied?
Is there any other precise generic definition of continuity? Is the $\epsilon,\delta$ definition is the one we only have? Is that definition generic enough?
You have your definition all wrong. The precise definition of continuity for real functions is:
An extension of this definition is: if a function is continuous at every point in $A$, then it is continuous on $A$. In formal language then, $f$ is continuous iff
$$ \forall x_0\in A\forall \epsilon>0\exists\delta>0\forall x:|x-x_0|<\delta\implies |f(x)-f(x_0)|<\epsilon $$
Now, you say "this $\epsilon, \delta$ definition implies continuity", which is not really true. This definition is the definition of continuity!
There are more definitions of continuity. For one, it is simple to prove that $f:A\to\mathbb R$ is continuous if and only if, for every convergent sequence $(a_n)$ in $A$, the equality $$f\left(\lim_{n\to\infty}a_n\right)=\lim_{n\to\infty}f(a_n)$$
Because this property is equivalent to continuity, it is an alternative definition of continuous functions.
More generally, the concept of continuous functions can be extended to all topological spaces. There, a function is continuous if for every open set $U$, the preimage of $U$ is also open, i.e. $f:X\to Y$ is continuous if $$\forall U\subseteq Y: U\text{ open in }Y\implies f^{-1}(U)\text{ open in }X$$