I am trying to understand what Hopf copairing means.
From the definition of a Hopf pairing we know that it is a bilinear form of two Hopf algebras $H$ and $K$, $(-,-): H \times K \rightarrow \mathbb{K}$, such that for any $h,g \in H$ and $x,y \in K$, we have:
(1) $(h,xy)=\sum(h_{1},x)(h_{2},y)$,
(2) $(hg,x)=\sum(h,x_{1})(g,x_{2})$,
(3) $(1,x)=\epsilon(x)$, $(h,1)=\epsilon(h)$,
(4) $(h, Sx)=(Sh,x)$.
How can we define a copairing of Hopf algebras and what does it mean?
Thank you in advance! :)
I'm assuming that you are using Sweedler notations, and I will denote $(A \otimes B)^{12}=A \otimes B \otimes 1$, similarly for $(A \otimes B)^{13}$ and $(A \otimes B)^{23}$. (There is an ambiguity for 1, it should be seen as the unit of H or K according to the context.)
I have found this definition for a Hopf Algebra Copairing:
A map $ \mathbb{K} \to H \otimes K $ such that $1 \mapsto R= \sum R^1 \otimes R^2$ is a Hopf Copairing if :
Is it relevant to you?
As for the meaning, I do not know how to interpret it, but I can give you some examples.
If $K=H$, and $R$ is an R-matrix of H, then it is also a copairing.
If $ K=H^{\star}$, and H finite dimensional, $\sum e_i \otimes e_i^{\star}$ is a copairing, where $e_i$ is a basis of H and $e_i^{\star}$ its dual basis.
I guess that if you have a pairing on H, K, it should induce a copairing on $H^{\star}, K^{\star}$. And conversely.