The motivation for this is to find a succinct name for a data type in a Python module.
Suppose I choose an integer $c$ and I want to talk about the set of numbers of the form $a + b\sqrt{c}$, where $a$ and $b$ are rational numbers. If $c = -1$, for example, then this set is called the set of Gaussian Rationals. Of course, we would usually think only of values of $c$ such that $|c|$ is non-square. If $|c|$ is a square, for example if $c = 4$, then we obtain either the set of rational numbers (if $c$ is nonnegative) or the set of Gaussian Rationals (otherwise).
Suppose, for example, that $c = 2$. What would the set of numbers of the form $a + b\sqrt{2}$ ($a$, $b$ rational) be called?
An obvious generalisation would be to cube and higher roots, for example numbers of the form $a + b \times 2^{1/3} + c \times 2^{2/3}$ where $a$, $b$ and $c$ are rational.
The standard notation for $\{a+b\sqrt{2}:a,b \in \mathbb{Q}\}$ is $\mathbb{Q}[\sqrt{2}]$. We use the square brackets when we're thinking about it as a ring, with addition and multiplication defined in the usual way.
As you know $\mathbb{Q}[x]$ is the ring of polynomials in $x$ with rational coefficients. The strict definition of $\mathbb{Q}[\sqrt{2}]$ is $\{p(\sqrt{2}) : p \in \mathbb{Q}[x]\}$. It just so happens that things like $a_0 + a_1\sqrt{2} + a_2(\sqrt{2})^2 + \cdots + a_n(\sqrt{2})^n$ all boil down to $a + b\sqrt{2}$ when you're done simplifying.
The field $\mathbb{Q}(\sqrt{2})$ is defined to be $\{p/q : p,q \in \mathbb{Q}[\sqrt{2}]\}$. As a set we have $\mathbb{Q}[\sqrt{2}] = \mathbb{Q}(\sqrt{2})$.
In the case of the generalisation $a + b\times 2^{1/3} + c\times 2^{2/3}$, this would be $\mathbb{Q}[\sqrt[3]{2}]$. The formal definition of $\mathbb{Q}[\sqrt[3]{2}]$ is $\{p(\sqrt[3]{2}) : p \in \mathbb{Q}[x]\}$. Again, things like $a_0 + a_1\sqrt[3]{2} + a_2(\sqrt[3]{2})^2 + \cdots + a_n(\sqrt[3]{2})^n$ will look like $a+b\sqrt[3]{2} + c(\sqrt[3]{2})^2$ when you're done.
You can add other stuff, e.g. \begin{array} 1\mathbb{Q}[\sqrt{2},\sqrt{3}] &=& \mathbb{Q}[\sqrt{2}][\sqrt{3}] = \{ a+b\sqrt{3} : a,b \in \mathbb{Q}[\sqrt{2}]\} \\ &=& \{a+b\sqrt{2}+c\sqrt{3}+d\sqrt{6} : a,b,c,d \in \mathbb{Q}\} \end{array}
Any generalisation you can come up with will be of he form $\mathbb{Q}[\alpha_1,\ldots,\alpha_k]$, where $\alpha_i \in \mathbb{C}$. Of course, there's no point choosing $\alpha_i \in \mathbb{Q}$. Once you have $\operatorname{i}$ involved, there's no point having any other $\alpha_i \in \mathbb{Q}[\operatorname{i}]$ (the Gaussian rationals).