Is there any geometric solution for this problem?
2026-03-30 00:04:17.1774829057
What is the area of shaded region in the figure shown?
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From $\triangle BCD$, (1) get $BC = 4 \sqrt 3$ and (2) get $[\triangle BCD] = ([2] + [3]) = 8 \sqrt 3$.
Let arc AC cut BD at X. From $\triangle ODX$, get [1] using sine law and area formula.
[2] = [sector OCX] – [1].
[3] = ([2] + [3]) – [2].
Find [s] by simple subtraction.