Consider a vector $\vec{x}$ in three dimensions and $3\times 3$ second rank symmetric tensor $\textbf{T}$.
What is the definition of $\nabla \cdot(\vec{x}\times\textbf{T})$?
Based on this answer, I expect that to be $\textbf{e}_i \partial_l\left(\varepsilon_{ljk} x_j T_{ki}\right)$, because $$(\vec{x} \times \textbf{T})_{li} = \varepsilon_{ljk} x_j T_{ki},\, \text{and }\, \,\nabla \cdot (\vec{x}\times\textbf{T}) = \textbf{e}_i \partial_l (\vec{x} \times \textbf{T})_{li}.$$
However, in this answer (between 5th and 6th line of the first calculation), it is written to be equal to $\mathbf{e}_i\partial_l(\varepsilon_{ijk}x_jT_{kl})$.
Am I missing something?